Respuesta :

Gasaqui

Answer:

To  get system B, the SECOND equation in system A was replaced by the sum of that equation and the FIRST equation multiplied by FOUR. The solution to system B IS de same as the solution to system A

Step-by-step explanation:

x-y=3  equation 1

-2x+4y=-2   equation 2

so, multiplying by four the equation 1 we have

4x-4y=12   equation 3

later sum equation 3 and equation 2 we have

2x=10

lublana

Answer:

1.Second equation

2.First equation

3.4

4. is the

Step-by-step explanation:

We are given that two system of equations

System A:[tex]x-y=3[/tex] (Equation I )

[tex]-2x+4y=-2[/tex]  ( Equation II)

And solution (5,2)

System B:[tex]x-y=3[/tex]  (Equation I)

[tex]2x=10[/tex]  ( equation II)

We have to fill correct value in the blank space

Equation one of system A is multiplied by 4 then we get

[tex]3x-4y=12[/tex]  (Equation III)

Adding second equation of system A and equation III

Then we get [tex]2x=10[/tex]

Solving equations of system B

We get x=[tex]\frac{10}{2}=5[/tex]

Substitute x= 5 in equation I of system B then we get

[tex]5-y=3[/tex]

[tex]y=5-3=2[/tex]

Hence, the solution of system B is (5,2).

Hence, to get system B , the second equation in system  A is replaced by the sum  of that equation   and equation I  is multiplied by 4 .The solution to system B is the same as the solution of system A.

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