Answer:
P1=P2
Explanation:
For a uniform density fluids, the pascal law say that :
[tex]P=P_0 +\rho gh[/tex]
Where P is the pressure inside the fluid, [tex]P_0[/tex] is the pressure over the fluid surface, [tex]\rho[/tex] is the fluid density and h is the deep.
For both cases the fluid is water, therefore the density[tex]\rho[/tex] is the same for both cases.
The same analysis apply for the deep h.
The equation for the lake:
[tex]P_1=P_0 + \rho gh[/tex]
For the tub
[tex]P_2=P_0 + \rho gh[/tex]
The pressure over the surface is the same for both cases, so is possible clearing Po and match the equations
[tex]\rho gh-P_1=\rho gh+P_2 \\P_1=P_2 \\\\P_1 / P_2=1[/tex]
