Answer:
The range of the projectile is 66.7 meters.
Explanation:
The range of a projectile is given by the following expression as :
[tex]R=\dfrac{v_o^2\ sin2\theta}{g}[/tex]..............(1)
[tex]v_o=37.2\ m/s[/tex]
[tex]\theta=14.1^{\circ}[/tex]
[tex]g=9.8\ m/s^2[/tex]
The range can be calculated using equation (1). Putting the values of all parameters we get :
[tex]R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}[/tex]
R = 66.7 meters
So, the range of the projectile is 66.7 meters. Hence, this is the required solution.
