Respuesta :
Answer:
94.7 %
Explanation:
The balanced chemical reaction is as follows -
2 S + 3 O₂ -----> 2 SO₃
Hence ,
The number of moles according to the chemical reaction is -
Moles of S = 2
Moles of O₂ = 3
Since ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
For Sulfur ,
w = 6.0 g
as we know the molecular mass of S = 32 ,
Hence ,
moles are calculated by using the above formula , and putting the respective values ,
n = w / m = 6 / 32 = 0.1871 mol
similarly for Oxygen ,
w = 5.0 g
as we know the molecular mass of O = 32 g/mol ,
Hence ,
moles are calculated by using the above formula , and putting the respective values ,
n = w / m = 5 / 32 = 0.15625 mol
Comparing the moles with the values from the the equation ,
Since , S is in excess ,
Therefore , O₂ is the limiting reagent ,
Hence O₂ will determine the moles of the product ,
Therefore ,
Using unitary method ,
From the chemical reaction ,
3 mol of O₂ will give 2 mol of SO₃
and ,
1 mol of O₂ will give 2 / 3 mol of SO₃
Therefore ,
0.15625 mol O₂ will give 2 / 3 * 0.15625 mol of SO₃
Hence ,
Moles of SO₃ produced = 0.1042 mol
since ,
n = w / m
w = n * m
molecular mass of SO₃ = 80 g/mol
w = Mass of SO₃ = 0.1042 mol * 80 g/mol = 8.340 g
The percentage yield is calculated as the actual yield divided by the theoretical yield multiplied by 100 .
Hence ,
Percentage yield = actual yield / theoretical yield * 100
From the question ,
actual yield = 7.9 g of SO₃
As calculated above ,
theoretical yield = 8.340 g
Percentage yield = 7.9 g / 8.340 g * 100 = 94.7 %
The study of chemicals and bonds is called chemistry. There are two types of elements these rare metals and nonmetals.
The correct answer is 94.7 %
What are moles?
- The mole is the base unit of the amount of substance in the International System of Units.
- It is defined as exactly 6.02214076×10²³ elementary entities, which may be atoms, molecules, ions, or electrons.
The balanced chemical reaction is as follows -
[tex]2S + 3O_2 -----> 2SO_3[/tex]
Hence, The number of moles according to the chemical reaction is -
- Moles of S = 2
- Moles of O₂ = 3
Since, Moles is denoted by the given mass divided by the molecular mass,
Hence,
[tex]n = \frac{w}{ m}[/tex]
where
- n = moles ,
- w = given mass ,
- m = molecular mass .
For Sulfur,
w = 6.0 g, as we know the molecular mass of S = 32,
Hence, moles are calculated by using the above formula, and putting the respective values,
n =[tex]\frac{w}{m} \\= \frac{6}{32}\\ = 0.1871 mol[/tex]
For Oxygen,
w = 5.0 g as we know the molecular mass of O = 32 g/mol,
Hence, moles are calculated by using the above formula, and putting the respective values,
n =[tex]\frac{w}{m} \\\\=\frac{5}{32}\\ = 0.15625 mol[/tex]
Comparing the moles with the values from the equation,
Since S is in excess, Therefore, O₂ is the limiting reagent,
Hence O₂ will determine the moles of the product,
Therefore, Using the unitary method,
From the chemical reaction, 3 moles of O₂ will give 2 mol of SO₃
and, 1 mole of O₂ will give 2 / 3 mole of SO₃
Therefore,
0.15625 mol O₂ will give[tex]\frac{2}{3} * 0.15625[/tex] mol of SO₃
Hence, Moles of SO₃ produced = 0.1042 mol
since,
[tex]n = \frac{w}{ m}w = n * m[/tex]
molecular mass of SO₃ = 80 g/mol
w = Mass of SO₃ = 0.1042 mol * 80 g/mol = 8.340 g
The percentage yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.
Hence, Percentage yield = actual yield / theoretical yield * 100
From the question, actual yield = 7.9 g of SO₃
As calculated above, theoretical yield = 8.340 g
Percentage yield = 7.9 g / 8.340 g * 100 = 94.7 %
For more information about the reaction, refer to the link:-
https://brainly.com/question/16759172
