For this case we have the following inequality:
[tex]x + \frac {1} {2} x-3> 2[/tex]
We add similar terms on the left side of the inequality:
[tex]\frac {2 + 1} {2} x-3> 2\\\frac {3} {2} x-3> 2[/tex]
We add 3 to both sides of the inequality:
[tex]\frac {3} {2} x> 2 + 3\\\frac {3} {2} x> 5[/tex]
We multiply by 2 on both sides:
[tex]3x> 5 * 2\\3x> 10[/tex]
We divide between 3 on both sides:
[tex]x> \frac {10} {3}[/tex]
The solutions are given by all values of x greater than [tex]\frac {10} {3}[/tex]
Answer:
[tex]x> \frac {10} {3}[/tex]
Answer:
Rewrite the inequality so there is a single rational expression on one side, and 0 on the other.
Combine under a common denominator.
Test points in the critical regions.
Construct the solution.
Step-by-step explanation:
its what edg said
