Gold has an atomic weight of 196.97 g/mol, and a density of 19.3 g/cm3. Approximately how many atoms are in a spherical gold nanoparticle 10 nm in diameter?

Respuesta :

Answer: The number of atoms in spherical gold nano particle are [tex]26.918\times 10^4[/tex]

Explanation:

  • To calculate the volume of sphere, we use the equation:

[tex]V=\frac{4}{3}\pi r^3[/tex]

where,

r = radius of the sphere = [tex]10nm=10^{-6}cm[/tex]    (Conversion factor:  [tex]1nm=10^{-7}cm[/tex] )

Putting values in above equation, we get:

[tex]V=\frac{4}{3}\times 3.14\times (10^{-6})^3\\\\V=4.19\times 10^{-18}cm^3[/tex]

  • To calculate mass of of the substance, we use the equation:

[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]

Volume of gold = [tex]4.19\times 10^{-18}cm^3[/tex]

Density of gold = [tex]19.3g/cm^3[/tex]

Putting values in above equation, we get:

[tex]19.3g/cm^3=\frac{\text{Mass of gold}}{4.19\times 10^{-18}}\\\\\text{Mass of gold}=8.0867\times 10^{-17}g[/tex]

  • To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Mass of gold = [tex]8.8067\times 10^{-17}g[/tex]

Molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of gold}=\frac{8.8067\times 10^{-17}g}{196.97g/mol}=4.47\times 10^{-9}moles[/tex]

  • According to mole concept:

1 mole of an element contains [tex]6.022\time 10^{23}[/tex]  number of atom

So, [tex]4.47\times 10^{-19}[/tex] moles of gold will contain = [tex]4.47\times 10^{-19}\times 6.022\times 10^{23}=26.918\times 10^4[/tex] number of atoms.

Hence, the number of atoms in spherical gold nano particle are [tex]26.918\times 10^4[/tex]