Answer:
The co-ordinates of the center of the cube are (-2.5,0.5,1.5)
Step-by-step explanation:
Since the 'z' co-ordinate of all the points is same hence we can conclude that all the given 4 points are planar.
Thus the problem reduces a planar problem with need to find the center of the square with vertices (-1,-3), (-1,4), (6,-3), (6,4)
Thus the length of the side of the square is[tex]side=\sqrt{(-1+1)^{2}+(4+3)^{2}}\\\\side=\sqrt{(7)^{2}}\\\\\therefore side=7\\[/tex]
[tex]\\[/tex]
The center of the square is given by taking (-1,-3) as reference co-ordinate
(-1+7/2,-3+7/2) = (-2.5,0.5)
Now since center lies above this center of base
Thus the coordinates of the center of the cube are given by (-2.5,0.5,-2+3.5)=(-2.5,0.5,1.5)
