Vanadium metal has a molar heat capacity of 24.9 J/mol·K. Given that q = Cm × n × ΔT, how many moles of vanadium are present if 3.27 ✕ 103 J of heat is required to raise the temperature of the sample by 36.7 K?

Respuesta :

Answer:

number of  moles present is 3.58 mol

Explanation:

given data

molar heat capacity C m= 24.9 J/mol·K

q = Cm × n × ΔT

heat require q =  3.27 × 10³ J

temperature ΔT = 36.7 K

to find out

number of  moles ( n )

solution

we have given equation

q = Cm × n × ΔT   .................1

put here all these value to find n by equation 1

q = Cm × n × ΔT

3.27 × 10³ = 24.9× n × 36.7

n = 3.27 × 10³ /  ( 24.9× 36.7 )

n  = 3.5783

so number of  moles present is 3.58 mol

The number of moles present int the vanadium metal to raise the temperature of the sample by 36.7 K is 3.5783.

What is heat capacity?

The heat capacity of a object is the property of it, due to which the object required a certain amount of heat to change its temperature of one degree.

The equation given in the poroblem is,

[tex]q = C_m \times n \times \Delta T[/tex]

Here, ([tex]C_m[/tex]) is the molar heat capacity of the substance and (n) is the number of moles.

Vanadium metal has a molar heat capacity of 24.9 J/mol·K and the 3.27 ✕ 10³ J of heat is required to raise the temperature of the sample by 36.7 K. Thus bu the above formula,

[tex]3.27\times10^{3}= 24.9 \times n \times 36.7\\n=3.5783[/tex]

Hence, the number of moles present int the vanadium metal to raise the temperature of the sample by 36.7 K is 3.5783.

Learn more about the heat capacity here;

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