Respuesta :
Answer: The concentration of [tex]Ca^{2+}\text{ and }Mg^{2+}[/tex] ions are 2.797 ppm and 0.212 ppm respectively.
Explanation:
To calculate the mass of solution, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Volume of gold = 100 L = 100000 mL (Conversion factor: 1 L = 1000 mL)
Density of gold = 1.001 g/mL
Putting values in above equation, we get:
[tex]1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g[/tex]
To calculate the concentration in ppm (by mass), we use the equation:
[tex]ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6[/tex]
- Calculating the concentration of calcium ions:
Mass of [tex]Ca^{2+[/tex] ions = 0.280 g
Putting values in above equation, we get:
[tex]ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm[/tex]
- Calculating the concentration of magnesium ions:
Mass of [tex]Mg^{2+[/tex] ions = 0.0220 g
Putting values in above equation, we get:
[tex]ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm[/tex]
Hence, the concentration of [tex]Ca^{2+}\text{ and }Mg^{2+}[/tex] ions are 2.797 ppm and 0.212 ppm respectively.
