A heterozygous tall pea plant is allowed to self-fertilize. The resulting F1 progeny are 25% homozygous tall, 50% heterozygous tall and 25% dwarf. If all of the F1 plants are allowed to self-fertilize, what percentage of the F2 progeny are dwarf?

Respuesta :

Answer:

25% heterozygous tall

Explanation:

If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.

The first one for homozygous tall, then we have 100% AA.

The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.

The last one would be for dwarf, and we'll have 100%aa.

Adding all of them, we'll have

AA = 100 + 25 + 25 = 150%

Aa =  50+50 = 100%

aa = 100 + 25 + 25 = 150%

as we had 4 crosses, so dividing the total percentages by 4, we'll have,

AA = 37.5%

Aa = 25%

aa = 37.5%

:. The percentage of heterozygous tall would be 25%.

Hope it helps:)

The percentage of the F2 progeny of dwarfs is 37.5%.

What is self-fertilization?

Self-fertilization is when the fusion of male and female gametes happens within the same plants.

Given,

F1 progeny is 25% similar tall

50% heterozygous tall and 25 % dwarf

To find the % of F2 progeny of dwarf

Adding all the results from the F1 generation

AA = 100 + 25 + 25 = 150%

Aa =  50+50 = 100%

aa = 100 + 25 + 25 = 150%

As we have four crosses, then divide the percentage by 4.

AA = 37.5%

Aa = 25%

aa = 37.5%

Thus, the percentage of F2 progeny of dwarfs is 37.5%

Learn more about fertilization, here:

https://brainly.com/question/3204813