contestada

The formula
d
=
1.3
t
2
+
t
+
2
expresses a car's distance (in feet to the north of an intersection,
d
, in terms of the number of seconds
t
since the car started to move.As the time
t
since the car started to move increases from
t
=
8
to
t
=
8.2
seconds, what constant speed must a truck travel to cover the same distance as the car over this 0.2-second interval?

Respuesta :

calculista

Answer:

The truck travel must to have a constant speed of [tex]22.06\ ft/sec[/tex]

Step-by-step explanation:

we have

[tex]d=1.3t^{2}+t+2[/tex]

where

d expresses a car's distance in feet

t is the number of seconds

Find the distance d for t=8 sec

[tex]d=1.3(8)^{2}+8+2=93.2\ ft[/tex]

Find the distance d for t=8.2 sec

[tex]d=1.3(8.2)^{2}+8.2+2=97.612\ ft[/tex]

The total distance in this interval of 0.2 sec is

[tex]97.612-93.2=4.412\ ft[/tex]

Find the speed of the car

Divide the total distance by the time

[tex]4.412/0.2=22.06\ ft/sec[/tex]

therefore

The truck travel must to have a constant speed of [tex]22.06\ ft/sec[/tex]

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