If ED = x + 4 and DB = 3x - 8, find ED, DB, and EB

Answer:
Part 1) [tex]ED=10\ units[/tex]
Part 2) [tex]DB=10\ units[/tex]
Part 3) [tex]EB=20\ units[/tex]
Step-by-step explanation:
we know that
EB=ED+DB
ED=DB -----> given problem
Substitute the given values and solve for x
[tex]x+4=3x-8[/tex]
[tex]3x-x=4+8[/tex]
[tex]2x=12[/tex]
[tex]x=6[/tex]
Find the value of ED
[tex]ED=x+4[/tex]
substitute the value of x
[tex]ED=6+4=10\ units[/tex]
Find the value of DB
Remember that
ED=DB
therefore
[tex]DB=10\ units[/tex]
Find the value of EB
EB=ED+DB
[tex]EB=10+10=20\ units[/tex]
Answer:
[tex]20 = EB[/tex]
[tex]10 = DB[/tex]
[tex]10 = ED[/tex]
Step-by-step explanation:
By definition, according to this cross-section model, point [tex]D[/tex] is the segment bisector of all segments, according to which segments they are in congruence with. Anyway, here is how it is done:
3x - 8 = x + 4
-3x - 3x
_____________
−8 = −2x + 4
-4 - 4
_____________
−12 = −2x
____ ____
−2 −2
[tex]6 = x[/tex][Plug this back into all expressions above to get the measurements of [tex]20 = EB[/tex], [tex]10 = DB[/tex], [tex]10 = ED[/tex]]
* Since point [tex]D[/tex] the segment bisector, you set the given equations equal to each other, then in the end, plug the x-value back into all expressions to get the length of [tex]EB[/tex].
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