Answer: acceleration:[tex]4 m/s^{2}[/tex]
velocity: [tex]26 m/s[/tex]
Explanation:
The complete question is written bellow:
A cat is moving at 18 m/s when it accelerates at [tex]4 m/s^{2}[/tex] for 2 seconds. What is his new velocity?
In this situation the following equation will be useful:
[tex]V=V_{o}+at[/tex]
Where:
[tex]V[/tex] is the cat’s final velocity (new velocity)
[tex]V_{o}=18 m/s[/tex] is the cat’s initial velocity
[tex]a=4 m/s^{2}[/tex] is the cat's acceleration
[tex]t=2 s[/tex] is the time
Solving the equation:
[tex]V=18 m/s+(4 m/s^{2})(2 s)[/tex]
[tex]V=26 m/s[/tex] This is the cat's new velocity
