Respuesta :
(a) Graph is attached
The velocity-time graph for the cart is attached.
On the x-axis, time is represented in seconds (s).
On the y-axis, velocity is represented in metres per second (m/s).
Since the cart travels constantly at 5 m/s, its velocity remains the same, so it is represented as a flat line, until a time of 10 seconds.
(b) The slope of the graph representes the acceleration
In a velocity-time graph, the slope of the graph represents acceleration (which is measured in metres per second square, [tex]m s^{-2}[/tex]). In fact, acceleration is defined as
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where [tex]\Delta v[/tex] is the change in velocity while [tex]\Delta t[/tex] is the change in time.
In the graph, we see that [tex]\Delta v[/tex] corresponds to the increment in the y-variable, while [tex]\Delta t[/tex] corresponds to the increment of the x-variable; so acceleration is also equal to
[tex]a=\frac{\Delta y}{\Delta x}[/tex]
which is the slope of the graph. In this particular case, the line is flat: this means that the slope is zero, so the acceleration is zero.

Answer:
A) The car started with a velocity = 5 m/s at time t = 0 seconds, and finish it path (that means its velocity = 0 m/s) at t = 10 seconds.
If we draw this two points: (0, 5) and (10, 0) we get a line, where x-variable represents time in seconds and y-variable represents the velocity of the car (see picture attached).
B) The slope of the plot obtained in point A is calculated as follows:
slope = (0 - 5)/(10 - 0) = -0.5
which represent the variation of velocity respect time, this is called acceleration. In this case, the acceleration is -0.5 m/s². The negative value indicates that the car is decreasing its velocity as time increase.
