Answer:
m = 359.24 kg
Explanation:
given data:
mass of ice = 200 kg
latent heat of steam = 2260 kJ/kg
latent heat of ice = 334 kJ/kg
from conservatioon of energy principle we know that
heat lost by steam will be equal to heat gained by ice
therefore we have
( ml + mcdt) = (ml + mcdt)
m*2.26*10^6 + m*4186*(100-30) = 200*3.33 *10^6 + 2000*4186 *30
m = 359.24 kg
