Respuesta :
Answer:
The height is 0.1014 m
Explanation:
Given that,
Mass = 0.0400 g
Charge [tex]q= 6.40\ \mu C[/tex]
Time t = 0.0420 s
Electric field [tex]E=7.80\times10^{2}\ N/C[/tex]
We need to calculate the electric force on the particle
Using formula of electric force
[tex]F=qE[/tex]
Put the value into the formula
[tex]F_{e}=6.40\times10^{-6}\times7.80\times10^{2}[/tex]
[tex]F_{e}=0.004992= 0.499\times10^{-2}\ N[/tex]
We need to calculate the gravitational force
Using formula of force
[tex]F=mg[/tex]
Put the value into the formula
[tex]F_{g}=0.0400\times10^{-3}\times9.8[/tex]
[tex]F_{g}=0.000392 = 0.392\times10^{-3}\ N[/tex]
We need to calculate the net force
[tex]F_{net}=F_{e}-F_{g}[/tex]
[tex]F_{net}=0.499\times10^{-2}-0.392\times10^{-3}[/tex]
[tex]F_{net}=0.004598= 0.4598\times10^{-2}\ N[/tex]
We need to calculate the acceleration
Using newton's law
[tex]F = ma[/tex]
[tex]a = \dfrac{F}{m}[/tex]
[tex]a=\dfrac{0.4598\times10^{-2}}{0.0400\times10^{-3}}[/tex]
[tex]a =114.95\ m/s^2[/tex]
We need to calculate the height
Using equation of motion
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
[tex]s=0+\dfrac{1}{2}\times114.95\times(0.0420)^2[/tex]
[tex]s=0.1014\ m[/tex]
Hence, The height is 0.1014 m
