Answer:
237.5 N
Explanation:
Force between two current carrying conductor per unit length ,
= [tex]\frac{\mu_0}{4\pi}\times\frac{2I_1I_2}{R}[/tex]
[tex]\frac{\mu_0}{4\pi} =10^{-7} , I_0=29 A, I_2=80A[/tex]
Putting these values , we get
F = 10⁻⁷ X [tex]\frac{2\times29\times80}{.37}[/tex]
F = 12.5 x 10⁻⁴ N per unit length
Force on entire length of wire
12.5 x 10⁻⁴ x 19
237.5 N
The force will be attractive i nature,.
