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A major force opposing the motion of a vehicle is the rolling resistance of the tires, Fr, given by Fr f w where f is a constant called the rolling resistance coefficient and w is the vehicle weight. Determine the power, in kW, required to overcome rolling resistance for a truck weighing 322.5 kN that is moving at 110 km/h. Let f 5 0.0069

Respuesta :

Answer:

[tex]P = 68 kW[/tex]

Explanation:

As we know that the friction force on the truck is given as

[tex]f_f = f W[/tex]

here we know that

[tex]W = 322.5 kN[/tex]

also we know that

[tex]f = 0.0069[/tex]

so friction force on the truck is given as

[tex]f_f = 0.0069 \times 322.5 \times 10^3[/tex]

[tex]f_f = 2225.25 N[/tex]

Speed of the truck is given as

[tex]v = 110 km/h[/tex]

[tex]v = 30.56 m/s[/tex]

now the power is given as

[tex]P = F.v[/tex]

[tex]P = (2225.25)(30.56)[/tex]

[tex]P = 68\times 10^3 W[/tex]

[tex]P = 68 kW[/tex]

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