Answer:
λ = h/p
[tex]E=2.41*10^{-17}Joules[/tex]
This energy is equivalent to E=150.44eV
Explanation:
de Broglie Equation:
λ = h/p
h=6.63×10-34 m2 kg / s Planck's constant
so: p=h/λ
On the other hand, an atomic distance, an angstrom, is equal:[tex]10^{-10}m[/tex], λ should be similar to this distance.
Kinetics Energy of a electron, m=9.11×10−31 kg
[tex]E=\frac{p^{2}}{2m_e}=\frac{h^{2}}{2\lambda^{2}m_e} =\frac{(6.63*10^{-34})^{2}}{2*(10^{-10})^{2}*9.11*10^{-31}}=2.41*10^{-17}Joules[/tex]
Number of volts needed to accelerate that electron from rest to this energy:
[tex]E=Vq_{e}[/tex]
[tex]V=E/q_{e}=2.41*10^{-17}/(1.602*10^{-19})=150.44Volts[/tex]
So, this energy is equivalent to E=150.44eV
This high-voltage device is called: particles accelerator
