Respuesta :
Answer:
Electric field will remain same.
Explanation:
Given that
At initial condition ,charge q = +3μ C
Electric field E = 4106 N/c
As we know that
Electric field due to charge q
[tex]E=\dfrac{kq}{r^2}[/tex]
Now when charge is replaced by new charge q'= -3μ C
From the expression of electric field we can say that electric field will remain same from same quantity of electric charge.
So we can say that electric field will remain same.
When the +3 µC charge is replaced with a charge of -3 µC, the magnitude of the electric field will be the same while the direction of the electric field will change.
If the test charge is replaced with a charge of -3 µC, what happens to the electric field at P?
We know that the electric field at any point is given as,
[tex]\overrightarrow E =\dfrac{kQ}{r^2}[/tex]
Now, since except the charge nothing is been changed, therefore, +3 µC will be replaced by -3 µC, thus the magnitude of the electric field will not change but since the value is coming out to be negative, therefore, the direction of the electric field will be changed.
Hence, when the +3 µC charge is replaced with a charge of -3 µC, the magnitude of the electric field will be the same while the direction of the electric field will change.
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