For this case we have the following inequalities:
[tex]2x> -10[/tex] intersected with [tex]3x <24[/tex]
So:
[tex]2x> -10[/tex]
Dividing between 2 on both sides:
[tex]x> - \frac {10} {2}\\x> -5[/tex]
The solution is given by all values of strict x greater than -5.
On the other hand we have:
[tex]3x <24[/tex]
Dividing between 3 on both sides:
[tex]x <\frac {24} {3}\\x <8[/tex]
The solution is given by all values of x less strict to 8.
Intersecting the solutions we have:
[tex](-5,8)[/tex]
Answer:
[tex]-5 <x <8[/tex]
