Answer:
m= 4.8 months
Step-by-step explanation:
by taking x as the money the International Business Club has at any time of the year,250.5 for their initial money, 35 as the money they spend every month and m being the month that have passed since the beginning of the school year; it all can be related to the following equation:
x= 250.5 - (35*m)
And doing the same thing with the money from the Future Agricultural Leaders Club, associating their money to the variable y, the equation would be:
y=300 - (45.25*m)
as it is wanted to know at what month does both clubs have the same amount of money, x and y, must be the same, so:
250.5 - (35*m) =300 - (45.25*m)
this equation can be solved by putting both terms that are related to m on the same side of the equality, and those who aren’t related on the other side:
(45.25*m) - (35*m)= 300 -250.5
then, on the first side of the equation, m can be taken out as common factor:
(45.35-35)*m=49,5
and solving for m:
m=[tex]\frac{49.5}{10.25}[/tex]
m=4.8
Answer: 250.5 – 35m = 300 – 45.25m
Step-by-step explanation: passed the test on edg;)
