Answer:
u = 2.01*10^{-4} Am^2
magnetic field strength = 3.91*10^{-8} m
Explanation:
a ) magnetic dipole moment i = u / πr^2
where,
i is current in the ring = 100 A
r is radius of ring = 1.60/2 =0.80 mm
[tex]100 A = \frac{u}{\pi * ( 0.8 *10^{-3 m} )^2}[/tex]
u = 2.01*10^{-4} Am^2
b ) [tex]x = \frac{u_0}{4\pi * ( \frac{2 u}{z^3} )}[/tex]
[tex]= \frac{4\pi *10^{-7}}{4 \pi \frac{2 * 2.01*10^{-4}}{( 5.40 *10^{-2} )^3}}[/tex]
magnetic field strength = 3.91*10^{-8} m