Answer : The heat energy needed would be, 6486.5125 J
Explanation :
To calculate the change in temperature, we use the equation:
[tex]q=mc\Delta T\\\\q=mc(T_2-T_1)[/tex]
where,
q = heat needed = ?
m = mass of aluminum = 223 g
c = specific heat capacity of aluminum = [tex]0.895J/g^oC[/tex]
[tex]\Delta T[/tex] = change in temperature
[tex]T_1[/tex] = initial temperature = [tex]22.5^oC[/tex]
[tex]T_2[/tex] = final temperature = [tex]55.0^oC[/tex]
Putting values in above equation, we get:
[tex]q=223g\times 0.895J/g^oC\times (55.0-22.5)^oC[/tex]
[tex]q=6486.5125J[/tex]
Therefore, the heat energy needed would be, 6486.5125 J
