Answer:
Speed of the boat, v = 4.31 m/s
Explanation:
Given that,
Height of the bridge, h = 32 m
The model boat is 11 m from the point of impact when the key was released, d = 11 m
Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 and a = g
[tex]t=\sqrt{\dfrac{2s}{g}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 32}{9.8}}[/tex]
t = 2.55 seconds
Let v is the speed of the boat. It can be calculated as :
[tex]v=\dfrac{d}{t}[/tex]
[tex]v=\dfrac{11\ m}{2.55\ s}[/tex]
v = 4.31 m/s
So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.
