Answer:
k = 104.46 N/m
Explanation:
Here we can use energy conservation
so we will have
initial gravitational potential energy = final total spring potential energy
as we know that she falls a total distance of 31 m
while the unstretched length of the string is 12 m
so the extension in the string is given as
[tex]x = L - L_o[/tex]
[tex]x = 31 - 12 = 19 m[/tex]
so we have
[tex]mgH = \frac{1}{2}kx^2[/tex]
[tex]62(9.81)(31) = \frac{1}{2}k (19^2)[/tex]
[tex]k = 104.46 N/m[/tex]