Answer:
a)t=4.5s
b)t=4.5s
Explanation:
Conceptual analysis
We apply the formula for (a) uniformly accelerated movement
[tex]a=\frac{vf-vi}{t}[/tex]formula (1)
a; acceleration in m/s²
vi:initial speed in m/s
vf:final speed in m/s
Problem development
a)We replace the known data in the formula (1)
a=2m/s², vi=16 m/s ,vf= 25 m/s?
[tex]2= \frac{25-16}{t}[/tex]
[tex]t = \frac{25-16}{2}[/tex]
[tex]t = \frac{9}{2} =4.5s[/tex]
b)a=2 m/s², vi=54 m/s ,vf= 63m / s?
[tex]2= \frac{63-54}{t}[/tex]
[tex]t = \frac{63-54}{2}[/tex]
[tex]t = \frac{9}{2} =4.5s[/tex]
