Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelope with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?

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Answer:

Step-by-step explanation:

Given that Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelope with its correct address. The 4 letters are to be put into the 4 envelopes at random.

Probability that only 1 letter will be put into the envelope with its correct address has to be calculated

If 1 is to be done right, all other three should be in wrong.

The possibilities of putting all three covered in wrong envelopes

(2,3,1) Or (3,1,2) hence only 2

The right one can be any one of 4.

Hence total no of ways of putting in the desired manner =4 (2) =8

Total no of ways of putting envelopes = 4! =24

Hence prob=[tex]\frac{8}{24} =\frac{1}{3}[/tex]