Answer:
0.31 seconds
Explanation:
Initial velocity of bag = -3 m/s = u (upward direction considered as positive)
Final velocity = 0 = v (touches the ground)
a = g = Acceleration due to gravity = 9.81 m/s²
t = Time taken to reach the ground
Equation of motion
[tex]v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-(-3)}{9.81}\\\Rightarrow t=\frac{3}{9.81}\\\Rightarrow t=0.31\ s[/tex]
∴ Time taken by the bag to reach the ground is 0.31 seconds
