A two-resistor voltage divider employing a 2-k and a 3-k resistor is connected to a 5-V ground-referenced power supply to provide a 2-V voltage. Sketch the circuit. Assuming exact-valued resistors, what output voltage (measured to ground) and equivalent output resistance result? If the resistors used are not ideal but have a ±5% manufacturing tolerance, what are the extreme output voltages and resistances that can result?

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lcmendozaf lcmendozaf · Answer 1 · 2019-09-19T03:56:15+02:00

Answer:

Rout=1.2K

Vmax=2.12V; Vmin=1.88V

Rmax=1.26K

Rmin=1.14K

Explanation:

You can find the circuit diagram attached.

Seing from the output and with no power supply, the output resistance will be R1 in parallel to R2:

Rout = R1 // R2 = 1.2K

The maximum output voltage will be when R1 = 3K-5% and R2 = 2K+5%:

[tex]Vmax = \frac{2.1K}{2.1K + 2.85K} *5V=2.12V[/tex]

Minimum voltage will be when R1 = 3K+5% and R2 = 2K-5%:

[tex]Vmin = \frac{1.9K}{1.9K + 3.15K} *5V=1.88V[/tex]

As for the output resistance:

Rmax will be when R1 = 3K+5% and R2 = 2K+5%:

Rmax = 1.26K

And Rmin will be when R1 = 3K-5% and R2 = 2K-5%:

Rmax = 1.14K