Respuesta :
Answer:
2.6143 m
Explanation:
For constructive interference, the expression is:
[tex]d\times sin\theta=m\times \lambda[/tex]
d is the distance between the slits.
The formula can be written as:
[tex]sin\theta=\frac {\lambda}{d}\times m[/tex] ....1
The location of the bright fringe is determined by :
[tex]y=L\times tan\theta[/tex]
Where, L is the distance between the slit and the screen.
For small angle , [tex]sin\theta=tan\theta[/tex]
So,
Formula becomes:
[tex]y=L\times sin\theta[/tex]
Using 1, we get:
[tex]y=L\times \frac {\lambda}{d}\times m[/tex]
For the single slit diffraction, the bright fringes are represented by the half-integers. The first such integer is, m = 1.5
y = ?
Given L = 10.0 m
d = 3.50 × 10⁻³ mm
Also, 1 mm = 10⁻³ m
So, d = 3.50 × 10⁻⁶ m
λ = 610 nm
Since, 1 nm = 10⁻⁹ m
So,
λ = 610 × 10⁻⁹ m
Applying the formula as:
[tex]y=10.0\ m\times \frac {610\times 10^{-9}\ m}{3.50\times 10^{-6}\ m}\times 1.5[/tex]
⇒ y, location of first bright fringe = 2.6143 m
