An object is placed 6.5 cm in front of a converging lens that has a focal length of 14 cm. Which one of the following statements is TRUE concerning the image? A) The image is virtual and 6.0 cm from the lens B) The image is virtual and 12 cm from the lens C) The image is real and 3.0 cm from the lens. D) The image is real and 6.0 cm from the lens. E) The image is real and 12 em from the lens

Respuesta :

Answer:

B) The image is virtual and 12 cm from the lens

Explanation:

u = Object distance =  6.5 cm

v = Image distance

f = Focal length = 14 cm

Lens Equation

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{14}-\frac{1}{6.5}\\\Rightarrow \frac{1}{v}=\frac{-15}{182} \\\Rightarrow v=\frac{-182}{15}=-12\ cm[/tex]

Focal length of the lens is -12 cm. The negative sign implies the image is virtual in nature.