Answer:
B) The image is virtual and 12 cm from the lens
Explanation:
u = Object distance = 6.5 cm
v = Image distance
f = Focal length = 14 cm
Lens Equation
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{14}-\frac{1}{6.5}\\\Rightarrow \frac{1}{v}=\frac{-15}{182} \\\Rightarrow v=\frac{-182}{15}=-12\ cm[/tex]
Focal length of the lens is -12 cm. The negative sign implies the image is virtual in nature.