Respuesta :
Answer: The molarity of HCl solution is 0.08 M.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of sodium carbonate = 0.525 g
Molar mass of sodium carbonate = 106 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of sodium carbonate}=\frac{0.525g}{106g/mol}=0.005mol[/tex]
The chemical reaction for the formation of chromium oxide follows the equation:
[tex]2HCl(aq.)+Na_2CO_3(aq.)\rightarrow 2NaCl(aq.)+H_2O(l)+CO_2(g)[/tex]
By Stoichiometry of the reaction:
1 mole of sodium carbonate reacts with 2 moles of HCl
So, 0.005 moles of sodium carbonate will react with = [tex]\frac{1}{2}\times 0.005=0.0025mol[/tex] of HCl
To calculate the molarity of HCl, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Moles of HCl = 0.0025 moles
Volume of solution = 31.00 mL = 0.031 L (Conversion factor: 1L = 1000 mL)
Putting values in above equation, we get:
[tex]\text{Molarity of HCl}=\frac{0.0025mol}{0.031L}=0.08M[/tex]
Hence, the molarity of HCl solution is 0.08 M.
