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Two Styrofoam balls with the same mass m = 9.00 × 10−8 kg and the same positive charge Q are suspended from the same point by insulating threads of length L = 0.705 m. The separation of the balls is d = 0.0221 m. What is the charge Q?

Respuesta :

Answer:

[tex]q = 3.87 \times 10^{-11} C[/tex]

Explanation:

As we know that the two styrofoam balls are suspended in equilibrium

so we will have

[tex]Tcos\theta = mg[/tex]

[tex]Tsin\theta = \frac{kqq}{d^2}[/tex]

also we know that

[tex]sin\theta = \frac{d}{2L}[/tex]

[tex]sin\theta = \frac{0.0221}{2(0.705)}[/tex]

[tex]\theta = sin^{-1}(0.0313) = 1.79 degree[/tex]

so we will have

now from above two equations we have

[tex]tan\theta = \frac{kq^2}{mgd^2}[/tex]

[tex]tan(1.79) = \frac{(9\times 10^9)q^2}{(9\times 10^{-8})(9.81)(0.0221)^2}[/tex]

[tex]q = 3.87 \times 10^{-11} C[/tex]

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