Answer:
v ≈ 22.2 mph
θ ≈ 7.8° west of north
Explanation:
vₓ = -3 mph
vᵧ = 22 mph
Finding the speed (magnitude of velocity):
v = √(vₓ² + vᵧ²)
v = √((-3)² + (22)²)
v ≈ 22.2 mph
Finding the direction
θ = atan(vᵧ / vₓ)
θ = atan(22 / -3)
θ ≈ -82.2° or 97.8°
θ is in the second quadrant, so θ ≈ 97.8°, or 7.8° west of north.
