Answer: A. [tex]4.3\times10^7[/tex]
Step-by-step explanation:
Given : A certain CD-ROM disk can store approximately [tex]6.0 \times 10^2[/tex] megabytes of information.
1 megabyte = [tex]10^6[/tex] bytes
Then, The storage capacity of CD-ROM disk will be :
[tex]10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8[/tex]
If an average word requires 14 bytes of storage, then the number of words can be stored :-
[tex]\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7[/tex]
Hence, number of words can be stored = [tex]4.3\times10^7[/tex]
