Suppose that the average weekly earnings for employees in general automotive repair shops is $450, and that the standard deviation for the weekly earnings for such employees is $50. A sample of 100 such employees is selected at random. Find the standard deviation of the sampling distribution of the means of average weekly earnings for samples of size 100

Respuesta :

Answer:  5

Step-by-step explanation:

We know that the standard deviation of the sampling distribution of the means is given by :_

[tex]SE=\sigma_x=\dfrac{\sigma}{\sqrt{n}}[/tex]

Given : The average weekly earnings for employees in general automotive repair shops is[tex]\mu=\ $450[/tex].

The standard deviation for the weekly earnings for such employees =[tex]\sigma= \$50.[/tex]

Now, the standard deviation of the sampling distribution of the means of average weekly earnings for samples of size[tex]n=100[/tex]:-

[tex]SE=\sigma_x=\dfrac{50}{\sqrt{100}}\\\\\Rightarrow\ SE=\dfrac{50}{10}\\\\\Rightarrow\ SE=5[/tex]

Hence, the standard deviation of the sampling distribution of the means of average weekly earnings for samples of size 100 = 5