The charge entering the positive terminal of an element is given by the expression q(t) = –16e-5.00t mC. The power delivered to the element is p(t) = 5.7e-3t W. Compute the current in the element as a function of time, the voltage across the element as a function of time, and the total energy delivered to the element in the time interval 0 < t < 100 ms.

Respuesta :

Answer:

[tex]i_{t} =90*e^{-5t}mA[/tex]

[tex]V_{t} = 63.33*e^{2t}Volts[/tex]

[tex]Energy=3.45 joules[/tex]

Explanation:

[tex]i_{t} =\frac{dq}{dt} = 90*e^{-5t}mA[/tex]

[tex]V_{t} =\frac{p(t)}{i(t)} = 63.33*e^{2t}Volts[/tex]

[tex]Energy=\int\limits^{100ms}_0 {p(t)} \, dt= (-1/3)*5.7e^{-3t}= 5.7/3*(1-e^{-0.3})=3.45 joules[/tex]