Answer:
[tex]i_{t} =90*e^{-5t}mA[/tex]
[tex]V_{t} = 63.33*e^{2t}Volts[/tex]
[tex]Energy=3.45 joules[/tex]
Explanation:
[tex]i_{t} =\frac{dq}{dt} = 90*e^{-5t}mA[/tex]
[tex]V_{t} =\frac{p(t)}{i(t)} = 63.33*e^{2t}Volts[/tex]
[tex]Energy=\int\limits^{100ms}_0 {p(t)} \, dt= (-1/3)*5.7e^{-3t}= 5.7/3*(1-e^{-0.3})=3.45 joules[/tex]