Respuesta :
Answer: The correct answer is Option 5.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
- For calcium cyanamide:
Given mass of calcium cyanamide = 65 g
Molar mass of calcium cyanamide = 80.1 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of calcium cyanamide}=\frac{65g}{80.1g/mol}=0.811mol[/tex]
Moles of water = 4.0 moles
The chemical equation for the reaction of calcium cyanide and water follows:
[tex]CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3[/tex]
By Stoichiometry of the reaction:
1 mole of calcium cyanamide reacts with 3 moles of water.
So, 0.811 moles of calcium cyanamide will react with = [tex]\frac{3}{1}\times 0.811=2.433mol[/tex] of water.
As, given amount of water is more than the required amount. So, it is considered as an excess reagent.
Thus, calcium cyanamide is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of calcium cyanamide produces 2 moles of ammonia.
So, 0.811 moles of calcium cyanamide will produce = [tex]\frac{2}{1}\times 0.811=1.6mol[/tex] of ammonia.
Hence, the correct answer is Option 5.
Answer:
1.6 mol
Explanation:
the answer above is correct. I dont know why someone rated it as 1/5 stars bc its all right
