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Virus A will damage the system with probability 0.3. Independently of it, virus B will damage the system with probability 0.5. Independently of A and B, virus C will damage the system with probability 0.6. What is the probability that the system will be damaged (by at least one of the viruses)?

Respuesta :

Answer:

0.86.

Step-by-step explanation:

Probability (None of the viruses will do any damage) = (1 - 0.3)(1-0.5)(1-0.6)

= 0.14.

Therefore the probability that at least one will do damage = 1 - 0.14 = 0.86.

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