You have 846 ml of 3.95 M HCl. Using a volumetric pipet, you take 268 ml of that solution and dilute it to 803 ml in a volumetric flask. Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution?

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kobenhavn kobenhavn · Answer 1 · 2019-09-11T14:28:10+02:00

Answer: The concentration of hydrochloric acid in the final solution is 0.72 M

Explanation:

According to the dilution law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 3.95 M

[tex]V_1[/tex] = volume of stock solution = 268 ml

[tex]M_2[/tex] = molarity of diluted solution = ?

[tex]V_2[/tex] = volume of diluted solution = 803 ml

[tex]3.95\times 268=M_2\times 803[/tex]

[tex]M_2=1.32M[/tex]

Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.

According to the dilution law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 1.32 M

[tex]V_1[/tex] = volume of stock solution = 100 ml

[tex]M_2[/tex] = molarity of diluted solution = ?

[tex]V_2[/tex] = volume of diluted solution = 184 ml

[tex]1.32\times 100=M_2\times 184[/tex]

[tex]M_2=0.72M[/tex]

Thus concentration of hydrochloric acid in the final solution is 0.72 M