Two identical charges q placed 2.0 mapart exert forces of magnitude 4.0 N on each other What is the value of the charge q? a) q 1.8 x 10- C b) q 2.1 x 10-5 C c) q 4.2 x

Respuesta :

Answer:

c) [tex]4.2*10^{-5}C[/tex]

Explanation:

Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:

[tex]F=\frac{kq_{1}q_{2}}{r^{2}}[/tex]

where k is a proportionality constant with the value [tex]k=9*10^{9}\frac{Nm^{2}}{C^{2}}[/tex]

In this case [tex]q_{1}=q_{2}=q[/tex], so we have:

[tex]F=\frac{kq^{2}}{r^{2}}[/tex]

Solving the equation for q, we have:

[tex]kq^{2}=Fr^{2}[/tex]

[tex]q^{2}=\frac{Fr^{2}}{k}[/tex]

[tex]q=\sqrt{\frac{Fr^{2}}{k}}[/tex]

Replacing the given values:

[tex]q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}[/tex]

[tex]q=4.2*10^{-5}C[/tex]