Answer:
16700Joules
Explanation:
Given parameters:
Mass of water = 86.8grams = 0.0868Kg
Initial temperature = 40°C, to kelvin, 40+273 = 313K
Final temperature = 86°C to kelvin, 86 + 273 = 359k
Solution:
This problem is to find the heat quantity Q that would be required to raise the temperature of the water through the given temperature.
Q = mc(T₂ - T₁)
where m is the mass of the water
c is the specific heat capacity of water = 4200JKg⁻¹K⁻¹
T₂ and T₁ are the final and initial temperatures respectively
Q = 0.086 x 4200 x (359-313) = 16,615.2Joules or 16700Joules
