A given line has the equation 10x+2y=-2.
What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
12)?
O y=-5x+12
5x+y=12
Oy-12=5(x-0)
5x+y=-1

Respuesta :

The equation of a line of the slope-intersection form is given by:

[tex]y = mx + b[/tex]

Where:

m: It's the slope

b: It is the cut-off point with the y axis

If two lines are parallel then their slopes are equal.

We have the following line:

[tex]10x + 2y = -2\\2y = -10x-2\\y = -5x-1[/tex]

Thus, the slope of the line is -5.

Therefore a parallel line is of the form:

[tex]y = -5x + b[/tex]

We replace the point [tex](0,12)[/tex]

[tex]12 = -5 (0) + b\\12 = b[/tex]

Finally, the equation is of the form:

[tex]y = -5x + 12[/tex]

Answer:

[tex]5x + y = 12[/tex]

It's A, y=5x+12. Hope I helped!!