2y = x + 3
5y = x - 7
7
What is the solution set of the given system?
{f-13.-4/3}}
{(1/3,4/3)
{l-29/3.-10/3}}
{(29/3, 10/3)

Respuesta :

Answer:

Solution:  { -29/3 , -10/3 }

Step-by-step explanation:

2y = x + 3  ---------> equ 1

5y = x - 7    equ 2

equ 1 - equ s  ====>     -3y = 10

                                         y =  -10/3

Put y = -10/3 in equ 1

        2 * (-10/3)   = x + 3

         -20/3         = x + 3

          (-20/3) - 3   = x

        (-20/3) - (9/3)  = x

         (-20 - 9) / 3    =x

                x = -29/3

Solution:  { -29/3 , -10/3 }

For this case we must solve the following system of equations:

[tex]2y = x + 3\\5y = x-7[/tex]

We clear "x" from the second equation:

[tex]x = 5y + 7[/tex]

We substitute in the first equation:

[tex]2y = 5y + 7 + 3\\2y = 5y + 10\\2y-5y = 10\\-3y = 10\\y = - \frac {10} {3}[/tex]

We look for the value of the variable "x":

[tex]x = 5 (- \frac {10} {3}) + 7\\x = - \frac {50} {3} +7\\x = - \frac {29} {3}[/tex]

Thus, the solution of the system is given by:

[tex](- \frac {29} {3}, - \frac {10} {3})[/tex]

Answer:

[tex](- \frac {29} {3}, - \frac {10} {3})[/tex]