Respuesta :
Answer:
Solution: { -29/3 , -10/3 }
Step-by-step explanation:
2y = x + 3 ---------> equ 1
5y = x - 7 equ 2
equ 1 - equ s ====> -3y = 10
y = -10/3
Put y = -10/3 in equ 1
2 * (-10/3) = x + 3
-20/3 = x + 3
(-20/3) - 3 = x
(-20/3) - (9/3) = x
(-20 - 9) / 3 =x
x = -29/3
Solution: { -29/3 , -10/3 }
For this case we must solve the following system of equations:
[tex]2y = x + 3\\5y = x-7[/tex]
We clear "x" from the second equation:
[tex]x = 5y + 7[/tex]
We substitute in the first equation:
[tex]2y = 5y + 7 + 3\\2y = 5y + 10\\2y-5y = 10\\-3y = 10\\y = - \frac {10} {3}[/tex]
We look for the value of the variable "x":
[tex]x = 5 (- \frac {10} {3}) + 7\\x = - \frac {50} {3} +7\\x = - \frac {29} {3}[/tex]
Thus, the solution of the system is given by:
[tex](- \frac {29} {3}, - \frac {10} {3})[/tex]
Answer:
[tex](- \frac {29} {3}, - \frac {10} {3})[/tex]