Answer:
[tex]\dot m = 2.74 kg/s[/tex]
Explanation:
given data:
pressure 1 MPa
diameter of pipe = 30 cm
average velocity = 10 m/s
area of pipe[tex] = \frac[\pi}{4}d^2[/tex]
[tex] = \frac{\pi}{4} 0.3^2[/tex]
A = 0.070 m2
WE KNOW THAT mass flow rate is given as
[tex]\dot m = \rho A v[/tex]
for pressure 1 MPa, the density of steam is = 4.068 kg/m3
therefore we have
[tex]\dot m = 4.068 * 0.070* 10[/tex]
[tex]\dot m = 2.74 kg/s[/tex]