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What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction equals StartFraction 1 Over 3 EndFraction plus StartFraction 5 Over 6 EndFraction x. = + x x = –5 x = –negative StartFraction 1 Over 6 EndFraction x = negative StartFraction 1 Over 6 EndFraction x = 5

Respuesta :

calculista

Answer:

[tex]x=-5/3[/tex]

Step-by-step explanation:

we have

[tex]x-\frac{2}{3} x-\frac{1}{2}=\frac{1}{3}+\frac{5}{6}x[/tex]

Solve for x

Multiply by 6 both sides to remove the fractions

[tex]6x-4x-3=2+5x[/tex]

Combine like terms

[tex]2x-3=2+5x[/tex]

[tex]5x-2x=-3-2[/tex]

[tex]3x=-5[/tex]

[tex]x=-5/3[/tex]

abidemiokin

The value of x is -5/3

Given the equation;

[tex]x-\frac{2}{3}x - \frac{1}{2}=\frac{1}{3}+\frac{5}{6}x[/tex]

Collect the like terms:

[tex]x-\frac{2}{3}x - \frac{5}{6} x =\frac{1}{3}+\frac{1}{2}\\ Find \ the \ LCM\\\frac{6x-4x-5x}{6}=\frac{2+3}{6}\\\frac{-3x}{6} =\frac{5}{6}\\-3x = 5\\x=\frac{-5}{3}[/tex]

Hence the value of x is -5/3

Learn more here; https://brainly.com/question/11602229

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