Explanation:
Given that,
Weight = 280 lbs
Height = 60 ft
Power = 3.50 hp
(a). We need to calculate the work done by the boom on the fireman
Using formula of work done
[tex]Work\ done =Weight\ \times height[/tex]
[tex]W'=W\times h[/tex]
Put the value into the formula
[tex]W'=280\times60[/tex]
[tex]W'= 16800 ftlbf[/tex]
[tex]W'=\dfrac{16800}{778.169}[/tex]
[tex]W'=21.59\ Btu[/tex]
The work done by the boom is 21.59 Btu.
(b). We know that,
1 hp = 550 ft lbf
So, [tex]P = 3.50\times550[/tex]
[tex]P=1925\ ft-lbf/s[/tex]
We need to calculate the time
Using formula of time
[tex]t = \dfrac{W}{P}[/tex]
Put the value into the formula
[tex]t=\dfrac{16800}{1925}[/tex]
[tex]t =8.7\ sec[/tex]
The time is 8.7 sec.
Hence, This is the required solution.
