Answer:
The rate is the magnitude of the electric field between the plates is [tex]2.444\times10^{12}\ V/ms[/tex]
Explanation:
Given that,
Radial distance r= 7.4 mm
Magnetic field [tex]B=2.0\times10^{-8}\ T[/tex]
Radius r'= 3.3 mm
We need to calculate the rate is the magnitude of the electric field between the plates changing
Using formula of magnetic field
[tex]B=\dfrac{\mu_{0}\epsilon_{0}r'^2}{2r}(\dfrac{dE}{dt})[/tex]
Put the value into the formula
[tex]\dfrac{dE}{dt}=\dfrac{B2r}{\mu_{0}\epsilon_{0}r'^2}[/tex]
[tex]\dfrac{dE}{dt}=\dfrac{2.0\times10^{-8}\times2\times7.4\times10^{-3}}{4\pi\times10^{-7}\times8.85\times10^{-12}\times(3.3\times10^{-3})^2}[/tex]
[tex]\dfrac{dE}{dt}=2.444\times10^{12}\ V/ms[/tex]
Hence, The rate is the magnitude of the electric field between the plates is [tex]2.444\times10^{12}\ V/ms[/tex]
