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A race car starts from rest on a circular track of radius 310 m. Its speed increases at the constant rate of 0.6 m/s 2 . At the point where the magnitudes of the radial and tangential accelerations are equal, determine the speed of the race car. Answer in units of m/s

Respuesta :

Answer:

The speed of the race car is 13.63 m/s.

Explanation:

It is given that,

Radius of the circular track, r = 310 m

Acceleration of the car, [tex]v = 0.6\ m/s^2[/tex]

We need to find the speed of the race car. In circular motion, the object moves under the action of centripetal acceleration which is given by :

[tex]a=\dfrac{v^2}{r}[/tex]

[tex]v=\sqrt{a\times r}[/tex]

[tex]v=\sqrt{0.6\times 310}[/tex]

v = 13.63 m/s

So, the speed of the race car is 13.63 m/s. Hence, this is the required solution.

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